Hollywood forums

Posted: **Sat Feb 22, 2025 8:37 am**

Just checking to make sure.

If I do:

for n = 0 to tableitems(mytable)-1
		If mytable[n] = "toberemoved" then RemoveItem(mytable, n)
next

then that can cause problems, as for example, suppose index 2 and index 3 are both to be removed, then when removing n=2, the next, n=3, is actually going to be checking index 4, skipping index 3, since table was reconstructed when removeitem was done and index 3 is moved to index 2, to fill the empty spot after removal.

But if I do:

Code: Select all

for n = tableitems(mytable)-1 to 0 step -1
		If mytable[n] = "toberemoved" then RemoveItem(mytable, n)
next

I suppose now it is completely safe, right? That nothing weird is happening here that would suddenly make it unsafe?

Posted: **Sun Feb 23, 2025 1:09 pm**

Bugala wrote: ↑Sat Feb 22, 2025 8:37 am I suppose now it is completely safe, right?

Should be safe, I think.

Code: Select all

mytable = {"0","1","2","3","4","5"}
mytable[3] = "toberemoved"
For n = TableItems(mytable)-1 To 0 Step -1
		If mytable[n] = "toberemoved" Then RemoveItem(mytable, n)
Next
For n = 0 To TableItems(mytable)-1
		DebugPrint(n, mytable[n])
Next

When I am unsure in such a case I would try the boundary values, for my example mytable[0] = "toberemoved" and mytable[5] = "toberemoved".

Posted: **Sun Feb 23, 2025 10:06 pm**

Good idea using those boundary values. I hadn't thought that before, going to keep that in mind to use it.

Hollywood forums

Safe to remove items from table when going backwards?

Safe to remove items from table when going backwards?

Re: Safe to remove items from table when going backwards?

Re: Safe to remove items from table when going backwards?